Eigenvalues and Eigenvectors

Summary

An eigenvector of a square matrix is a nonzero vector mapped to a scalar multiple of itself. Eigenvalues are those scalars. The spectral picture diagonalizes (or Jordan-reduces) linear maps and underpins differential equations, PCA, and stability analysis.

Prerequisites

Determinants, Vector Spaces and Bases, Matrices and Row Reduction. Hub: Linear Algebra.

Definition / Statement

Let ARn×n (or Cn×n ). A scalar λ is an eigenvalue of A if there exists a nonzero vector v (an eigenvector) such that

Av=λv.

Equivalently,

(AλI)v=0,v0,

so AλI is singular:

det(AλI)=0.

The polynomial pA(λ)=det(AλI) is the characteristic polynomial (degree n ).

Objects and Dimensions

Object Meaning Dimensions
A square matrix n×n
λ eigenvalue scalar
v eigenvector n×1 , nonzero
Eλ=Nul(AλI) eigenspace subspace of Rn or Cn

Notation

Symbol Meaning
Av=λv eigen-equation
pA(λ)=det(AλI) characteristic polynomial
algebraic multiplicity multiplicity of λ as a root of pA
geometric multiplicity dimEλ

Conditions / Assumptions

Matrix / Vector Form

Characteristic equation

det(AλI)=0.

Diagonalization: if A=PDP1 with D=diag(λ1,,λn) and columns of P eigenvectors, then

Ak=PDkP1

for integers k0 (and for negative k if A is invertible, i.e. no zero eigenvalue).

Trace and determinant (counting algebraic multiplicity):

tr(A)=iλi,det(A)=iλi.

Geometric Interpretation

Worked Example

A=(2112). AλI=(2λ112λ),det(AλI)=(2λ)21=(λ1)(λ3).

Eigenvalues λ=1 and λ=3 .

For λ=1 : (AI)v=0 gives v1+v2=0 , so v=1,1 .

For λ=3 : (A3I)v=0 gives v1+v2=0 , so v=1,1 .

Common Mistakes

Connections

References

Eigenvalue theory as in MIT 18.06.[1]


  1. MIT OpenCourseWare, 18.06 Linear Algebra, https://ocw.mit.edu/courses/18-06-linear-algebra-spring-2010/ ↩︎